Question

In triangle ABC median AM is such that angle bac is divided in the ratio 1:2 and AM is extended through m to d so that angle dba is right angle then prove a.c. is half of ad

Answer 1

Answer:

1) First draw a circle with a radius of 1

2)The center is at point A

3) And draw a horizontal line through A

4) Draw another line thru A at an angle BAC (from your drawing), extend the line to a length of 0.5 from A, the end is point C

5) Draw another line thru A at an angle of 1/3 of BAC, extend that line to a length of 1 (to the perimeter of the circle. This point is D.

6) From D draw a vertical line the the horizontal line, they meet at point B.

7) You will have an Triangle ABC, and a line AD with length of AC=0.5*AD, and angle BAC is 3* the angle of BAD.

8) so here we can clearly observe that AC=0.5*AD

Answer 2

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