Question

factorise 9(3x+1)² - 2(x-1)² please answer fast​

Answer 1

Answer:

9(9x²+1+6x)-2(x²+1-2x). {(a+b)². = a²+b²+2ab}

{(a-b)². = a²+b²-2ab}

and then uu can. solve it...

Answer 2

Answer:

$⟹8(3−x)(2x+1)$

Step-by-step explanation:

factor it using following identities,

$(a+b)^{2} =a {}^{2} +2ab+ {b}^{2}$

$(a−b) {}^{2} =a {}^{2} −2ab+ {b}^{2}$

Similarly

$(3x+5) {}^{2} −(5x−1) {}^{2} =(9x {}^{2} +30x+25)−(25x {}^{2} −10x+1)$

$=9x {}^{2} +25+30x−25x {}^{2} +10x–1$

Separate the like terms,

$=9x {}^{2} −25x {}^{2} +30x+10x–1+25$

=−

$- 16x {}^{2} +40x+24$

$=−8(2x {}^{2} −5x−3)$

$=−8(2x {}^{2} +x−6x−3)$

$=−8[x(2x+1)−3(2x+1)]$

$= −8(x−3)(2x+1)$

$⟹8(3−x)(2x+1)$

Hope this answer helped you out,

have a nice day..✌