Question

Solve the following (0)
Ritu borrowed Rs. 25000 from a bank
hat the rate of 8 p. c.pc for 3 years.
How much amount did she retum to
the bank at the end of the portod?​

Answer 1

➤ Correct Question :-

Ritu borrowed Rs. 25000 from a bank at the rate of 8% for 3 years. How much amount did she return to the bank at the end of the period ?

➤ Given :-

Principle :- ₹ 25000

Rate of interest :- 8%

Time :- 3 years

➤ To Find :-

Total amount returned to the bank..........

➤ Formula required :-

${\large \tt \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{P \times R \times T}{100} + Principle}}}}$

➤ Solution :-

First, we should find the simple interest by multiplying principle, rate and time and then divided by 100..........

Simple Interest :-

$\tt \longrightarrow \dfrac{25000 \times 8 \times 3}{100}$

${\tt \longrightarrow \dfrac{\cancel{25000} \times 8 \times 3}{\cancel{100}} = \boxed{\tt 250 \times 8 \times 3}}$

${\tt \longrightarrow 200 \times 3 = \boxed{\tt Rs \: \: 600}}$

Now,

Total amount :-

${\tt \longrightarrow 25000 + 600}$

${\tt \longrightarrow Rs \: \: 25600}$

$\Huge\therefore$ The total amount to be paid at end of the period is ₹ 25600.

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$\dashrightarrow$ Some related formulas :-

Simple Interest :- ${\boxed{\tt\dfrac{P \times R \times T}{100}}}$

Principle :- ${\boxed{\tt\dfrac{SI \times 100}{R \times T}}}$

Rate of interest :- ${\boxed{\tt\dfrac{SI \times 100}{P \times T}}}$

Time :- ${\boxed{\tt\dfrac{SI \times 100}{P \times R}}}$

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More to know..................

• Simple Interest is the extra amount to be given when a person borrows some money from a person or a bank. The person who gives money is called lender. The person who takes money is called borrower.
• Principal is the amount given at first from lender to borrower.
• Rate of interest is the extra amount to be given from borrower to lender. It is always written in percentage format.
• Time is given for the borrower to return back the given money with the given interest.

Answer 2

Step-by-step explanation:

➤ Correct Question :-

Ritu borrowed Rs. 25000 from a bank at the rate of 8% for 3 years. How much amount did she return to the bank at the end of the period ?

➤ Given :-

Principle :- ₹ 25000

Rate of interest :- 8%

Time :- 3 years

➤ To Find :-

Total amount returned to the bank..........

➤ Formula required :-

{\large \tt \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{P \times R \times T}{100} + Principle}}}}⇢

100

P×R×T

+Principle

➤ Solution :-

First, we should find the simple interest by multiplying principle, rate and time and then divided by 100..........

Simple Interest :-

\tt \longrightarrow \dfrac{25000 \times 8 \times 3}{100}⟶

100

25000×8×3

{\tt \longrightarrow \dfrac{\cancel{25000} \times 8 \times 3}{\cancel{100}} = \boxed{\tt 250 \times 8 \times 3}}⟶

100

25000

×8×3

=

250×8×3

{\tt \longrightarrow 200 \times 3 = \boxed{\tt Rs \: \: 600}}⟶200×3=

Rs600

Now,

Total amount :-

{\tt \longrightarrow 25000 + 600}⟶25000+600

{\tt \longrightarrow Rs \: \: 25600}⟶Rs25600

\Huge\therefore∴ The total amount to be paid at end of the period is ₹ 25600.

━━━━━━━━━━━━━━━━━━━━━━

\dashrightarrow⇢ Some related formulas :-

Simple Interest :- {\boxed{\tt\dfrac{P \times R \times T}{100}}}

100

P×R×T

Principle :- {\boxed{\tt\dfrac{SI \times 100}{R \times T}}}

R×T

SI×100

Rate of interest :- {\boxed{\tt\dfrac{SI \times 100}{P \times T}}}

P×T

SI×100

Time :- {\boxed{\tt\dfrac{SI \times 100}{P \times R}}}

P×R

SI×100