Math, asked by rajkhorwalkhorwal, 9 months ago

factorise 9(a-b)^2-4(2a-b)-13​

Answers

Answered by ts0443430
0

Answer:

Xxx huffy kvxxjhxzgjjvxd

Answered by abdulhaadiy10
0

Answer:hope helps you

Step-by-step explanation:

Given 9(2a - b)^2 - 4(2a - b) - 13

= > 9(2a - b)(2a - b) + 9(2a - b) - 13(2a - b) - 13

= > 9(2a - b)[(2a - b) + 1] - 13[(2a - b) + 1]

= > (2a - b + 1)(18a - 9b - 13).

Similar questions