Factorise 9(x+2)²-4(x-1)² by taking out common factors
Answers
Answered by
0
Answer:
Step-by-step explanation:
9(3x+2)²-4(2x-1)²
=[3(3x+2)]²-[2(2x-1)]²
=(9x+6+4x-2)(9x+6-4x+2) [a²-b²=(a+b)(a-b)]
=(13x+4)(5x+8)
Answered by
3
Answer:
5x² + 44x + 32
Step-by-step explanation:
9(x+2)² -4(x-1)²
= {3(x+2)}² - {2(x-1)}²
= (3x + 6)² - (2x-2)²
= {(3x + 6) + (2x - 2)}×{(3x+6)-(2x-2)}
= (5x + 4)(x +8)
= 5x²+40x+4x+32
= 5x² + 44x + 32
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