factorise 9-x^2+2xy-y^2
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Step-by-step explanation:
9−x
2
+2xy−y
2
Above terms can be written as,
9−x
2
+xy+xy−y
2
Now,
=9−x
2
+xy+3x−3x+3y−3y+xy−y
2
Rearranging the above terms , we get,
=9−3x+3y+3x−x
2
+xy+xy−3y−y
2
Take out common in all terms ,
=3(3−x+y)+x(3−x+y)+y(−3−y+x)
=3(3−x+y)+x(3−x+y)−y(3+y−x)
=(3−x+y)(3+x−y)
Thus, factors are (3−x+y) and (3+x−y)
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