Manali lent Some amount to shalu at a Certain rate of Compound interest. Interest at the end of 2 years and 3 years was Rs 945 and 1521 Respectively. What was the rate of intereste?
Answers
Given
and
From (i)/(ii) and put (1 + r) = x
Now, (1 + r) = 7/6
r = 1/6 = 16.67%
see the image
Solution :-
Let us assume that, rate of interest is R% per annum and Principal is Rs.P .
So,
→ CI for 2 years = P[{1 + (R/100)}² - 1] = 945
and,
→ CI for 3 years = P[{1 + (R/100)}³ - 1] = 1521
Let us assume that, {1 + (R/100)} = x .
then,
→ (2 year CI / 3 year CI) = (x² - 1) / (x³ - 1) = 945 / 1521
→ (x - 1)(x + 1)/(x - 1)(x² + x + 1) = 105/169
→ (x + 1)/(x² + x + 1) = 105/169
→ 169x + 169 = 105x² + 105x + 105
→ 105x² - 64x - 64 = 0
→ 105x² - 120x + 56x - 64 = 0
→ 15x(7x - 8) + 8(7x - 8) = 0
→ (7x - 8)(15x + 8) = 0
→ x = (8/7) and (-15/8)
taking x = (8/7)
→ 1 + (R/100) = (8/7)
→ (R/100) = (8/7) - 1
→ (R/100) = (1/7)
→ R = (100/7) % (Ans.)
[ when we taken x = (-15/8) rate will be in negative which is not correct . ]
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