Question

Factorise....................

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Answer 1

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$27 {p}^{3} - \frac{1}{216} - \frac{9}{2} {p}^{2} + \frac{1}{4} p$

$= {(3p)}^{3} - {( \frac{1}{6} }^{} )^{3} - 3 \times {(3p)}^{2} \times \frac{1}{6} + 3 \times 3p \times {( \frac{1}{6} )}^{2}$

$= {(3p - \frac{1}{6}) }^{3}$

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