Question

Factorise 9a^2+4b^2+16c^2+12ab-16bc-24ca
$(a + b + c) ^{2}$

Answer 1

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Answer 2

=(3a)^2+(2b)^2+(-4c)^2+2(3a)(2b)+2(2b)(-4c)+2(-4c)(3a)
=(3a+2b-4c)^2