Question

Factorise 9a^2-4b^2-6a+1

Answer 1

I have written it by myself please mark it as the brainllist if it will help you

Answer 2

9a² - 4b² - 6a + 1 = ( 3a + 2b - 1 ) ( 3a - 2b - 1 )

Given :

9a² - 4b² - 6a + 1

To find :

To factorise the given expression

Formula :

a² - b² = ( a + b ) ( a - b )

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

9a² - 4b² - 6a + 1

Step 2 of 2 :

Factorise the expression

We factorise it as below

$\sf 9 {a}^{2} - 4 {b}^{2} - 6a + 1$

$\sf = 9 {a}^{2} - 6a + 1 - 4 {b}^{2}$

$\sf = {(3a)}^{2} - 2 \times 3a \times 1 + {1}^{2} - {(2b)}^{2}$

$\sf = {(3a - 1)}^{2} - {(2b)}^{2}$

$\sf = (3a - 1 + 2b) (3a - 1 - 2b)$

$\sf = (3a + 2b - 1) (3a - 2b - 1)$

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