Question

factorise 9a^2-6a+1​

Answer 1

$9 {a}^{2} - 6a + 1$

$9 {a}^{2} - (3 + 3)a + 1$

$9 {a}^{2} - 3a - 3a + 1$

$3a(3a - 1) - 1(3a - 1)$

$(3a - 1)(3a - 1)$

${(3a - 1)}^{2}$

hope it helps you ☆☆☆☆☆☆☆☆☆

Answer 2

$\textbf{\huge\underline{\underline\red{Solution} : - }} \\ \\ = > \bold{ \purple{9{a}^{2} - 6a + 1}} \\ \\ = > \bold{ \purple{9{a}^{2} - 3a - 3a + 1}} \\ \\ = > \bold{ \purple{3a(3a - 1) -1( 3a - 1)}} \\ \\ = > \bold{ \purple{(3a - 1)(3a - 1)}} \\ \\ = > \bold{ \purple{ {(3a -1) }^{2} }} \\ \\ \bold{ \underline \purple{i \: hope \: it \: helps \: you.}}$