Factorise 9a^2- 9b^2 + 6a + 1
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Answered by
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Given Equation is 9a^2 - 9b^2 + 6a + 1.
It can be written as:
9a^2 + 6a + 1 - 9b^2
(3a^2 + 1)^2 - 9b^2
(3a + 1)^2 - (3b)^2
We know that a^2 - b^2 = (a + b)(a - b)
(3a + 1 + 3b)(3a + 1 - 3b).
Hope this helps!
It can be written as:
9a^2 + 6a + 1 - 9b^2
(3a^2 + 1)^2 - 9b^2
(3a + 1)^2 - (3b)^2
We know that a^2 - b^2 = (a + b)(a - b)
(3a + 1 + 3b)(3a + 1 - 3b).
Hope this helps!
siddhartharao77:
:-)
Answered by
19
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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