factorise:- 9a^2-(a^2-4)^2
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Answered by
18
Hey Dear here is Your Answer... =)
9a^2-(a^2-4)^2
= ( 3a )^2 - ( a^2 - 4a)^2
= ( 3a - ( a^2 - 4 )) ( 3a + ( a^2 - 4 ))
= ( 3a - ( a^2 - 2^2 )) ( 3a + ( a^2 - 2^2 ))
=> ( 3a - ( a - 2) ( a + 2 )) ( 3a + ( a - 2 ) ( a + 2 )) ( ANS )
Hope it helps You Out =)
Thanks (^^)
Pls Mark it as The BRAINLIEST....!
9a^2-(a^2-4)^2
= ( 3a )^2 - ( a^2 - 4a)^2
= ( 3a - ( a^2 - 4 )) ( 3a + ( a^2 - 4 ))
= ( 3a - ( a^2 - 2^2 )) ( 3a + ( a^2 - 2^2 ))
=> ( 3a - ( a - 2) ( a + 2 )) ( 3a + ( a - 2 ) ( a + 2 )) ( ANS )
Hope it helps You Out =)
Thanks (^^)
Pls Mark it as The BRAINLIEST....!
Answered by
9
Here is your answer
See down
In pic
Tell me that I am correct or not please
See down
In pic
Tell me that I am correct or not please
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its wrong dear
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