Question

factorise 9a²-(2x-y)²​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$(3a +2x -y)(3a -2x +y)$ is the required value of $9a^2 - (2x - y)^2$

Step-by-step explanation:

Explanation:

Given in the question, $9a^2 - (2x - y)^2$

• Factorization - Writing a number or other mathematical object as the result of numerous factors typically smaller or simpler objects of the same kind is known as factorization or factoring in mathematics.

• Factorising is the process of employing brackets to represent an expression as the product of its factors. We accomplish this by eliminating any elements that are shared by all of the expression's terms.

Step 1:

We have, $9a^2 - (2x - y)^2$

⇒This can be written as,

⇒$(3a)^2$ - $(2x -y)^2$

⇒$[3a + (2x -y)][3a - (2x - y)]$

⇒$(3a +2x -y)(3a -2x +y)$

Final answer:

Hence, $(3a +2x -y)(3a -2x +y)$ this is the required answer.

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