factorise (9a2+3a-8b-64b2)
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9a2 + 3a - 8b - 64b2
lets take first 2 terms
= 9a2 + 3a
both have 3 and a in common
= 3a(a+1)
lets take left terms
=-8b-64b2
both have - , 8 and b in common
= -8b(1+8b)
hence it can't be factorise
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