Question

factorise 9a²+4b²+16c²+12ab-16bc-24ca

Answer 1

9a2 + 4b2 + 16c2 +12ab-16bc-24ca-
3a + 2a + 4c +(2x3a×2a)-(2×2a×4c)-(2×4c×3a)
so ,
a=3a
b=2b
c=4c
then the formula is (a+b+c)whole square
put the value of a b c
it gives- (3a+2b+4c) whole square
I hope it will helps

Answer 2

Answer:

9a² + 4b² + 16c² + 12ab - 16bc - 24ca

=> ( - 3a )² + ( - 2b )² + ( 4 c )² + 2[ ( -3a × -2b ) + ( -2b × 4c ) + ( 4c × - 3a ) ]

We know, a² + b² + c² + 2( ab + bc + ca ) = ( a + b + c )²

Hence,

=> [ ( -3a ) + ( -2b ) + ( 4c ) ]²

=> ( -3a - 2b + 4c )²

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