Math, asked by Ansh983646, 7 days ago

factorise: 9m²n²-16 ​

Answers

Answered by sahilsbade
0

Answer:

(3mn + 4)(3mn - 4)

Step-by-step explanation:

9m^2n^2 - 16

= (3mn)^2 - (4)^2

= (3mn+4)(3mn-4) [a^2 - b^2 = (a + b)(a - b)]

Answered by mahakulkarpooja615
1

Answer:

The factors of the expression 9m^{2} n^{2} -16 is (3mn+4)(3mn-4).

Step-by-step explanation:

Given : 9m^{2} n^{2} -16

To find : The factors of the given expression.

Solution :

  • The given expression is 9m^{2} n^{2} -16
  • We have to find the factors of the given expression.
  • We know the identity that,

        a^{2} -b^{2} =(a+b)(a-b)

  • Here, a=3mn and b=4.
  • So, the given expression becomes,

       9m^{2} n^{2} -16 = (3mn)^{2} -(4)^{2}

                        =(3mn+4)(3mn-4)

  • ∴ The factors of the expression 9m^{2} n^{2} -16 is (3mn+4)(3mn-4).

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