Question

factorise 9x^2 +27x + 20

Answer 1

Here is your answer .....................
9x²+27x+20
9x²+(15+12)x+20
9x²+15x+12x+20
3x(3x+5)+4(3x+5)
(3x+4) (3x+5)
x=-4/3,-5/3
hope it will help u... ☺
ples mark brainliest....
SSA/!\

Answer 2

$9x^{2} +27x+20$

For a polynomial of the form $ax^{2} +bx+c ,$ rewrite the middle term as a sum of two terms whose product is a × c = 9×20 = 180  and whose sum is  b = 27.

Factor $27$ out of  $27x$.

$9x^{2} +27(x)+20$

Rewrite $27$ as $12$ plus $15$

$9x^{2} +(12+15)x+20$

Apply the distributive property.

$9x^{2} +12x+15x+20$

Factor out the greatest common factor from each group.

$(9x^{2} +12x)+15x+20$

Factor out the greatest common factor (GCF) from each group.

$3x(3x+4)+5(3x+4)$

Factor the polynomial by factoring out the greatest common factor,$3x+4 .$

$(3x+4)(3x+5)$

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