Question

factorise 9x^(2)+4y^(2)+16z^(2)+12xy−16yz−24xz

Answer 1

9x^2+4y^2+16z^2+12xy -16yz-24xz

=(3x)^2+(2y)^2+(-4z)^2+2(3x)(2y)+2(2y)(-4z)+2(-4z)(3x)

This is of the form a^2+b^2+c^2+2ab+2bc+2ca

Which is equal to (a+b+c)^2

Hence 9x^2+4y^2+16z^2+12xy -16yz-24xz

= (3x+2y-4z)^2

I hope this helps

Answer 2

Hii buddy!!!!!!

ANSWER = Using the identity (a + b + c) = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca
=> 9x^2 + 4y^2 + 16z^2 + 12xy - 16yz - 24xz
=> (3x)^2 + (2y)^2 + (-4z)^2 + 2 * 3x * 2y + 2 * 2y * (-4z) + 2 * (-4z) * (3x)

=> (3x + 2y - 4z)^2
=> (3x + 2y - 4z) ( 3x + 2y - 4z)

Hope helps!!

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