FACTORISE:- 9x^3y+41x^2y+20xy^3
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Answered by
11
xy (9x + 5y) (x + 4)
Step-by-step explanation:
Given,
9x³y + 41x²y + 20xy³
Taking out xy as common:
xy (9x² + 41x + 20y²)
Splitting the middle term:
xy (9x²+ 36xy + 5xy + 20y²)
Grouping together:
xy [(9x²+ 36xy) + (5xy + 20y²) ]
Taking out common:
xy [9x (x + 4) + 5y (x + 4)]
xy (9x + 5y) (x + 4)
∴ The factors are xy (9x + 5y) (x + 4)
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Factorise the following
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Answered by
6
Answer:
Here is the answer for your question.
Step-by-step explanation:
9x³y + 41x²y + 20xy³
xy (9x² + 41x + 20y²)
xy (9x²+ 36xy + 5xy + 20y²)
xy [(9x²+ 36xy) + (5xy + 20y²) ]
xy [9x (x + 4) + 5y (x + 4)]
xy (9x + 5y) (x + 4)
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