Factorise 9x^4 +26x² -3
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Hey,
Assume x^2 to be any variable say t
Then, 9t^2+26t-3=0
Lets factorise it, using middle term split
9t^2+27t-t-3=0
9t(t+3) -1(t+3)=0
(t+3)(9t-1)=0
t=-3, t= 1/9
Now we assumed t to be x^2 so back up
x²=-3 (which is not possible)
x²=1/9=+-1/3
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