Question

factorise 9x(6x-5y)-12x square (6x-5y) I need it urgent

Answer 1

The factorisation of 9x(6x - 5y) - 12$x^2$(6x - 5y) is equal to 3x(6x - 5y)(3 - 4x).

Step-by-step explanation:

We have,

9x(6x - 5y) - 12$x^2$(6x - 5y)

To find, the factorisation of 9x(6x - 5y) - 12$x^2$(6x - 5y) = ?

∴ 9x(6x - 5y) - 12$x^2$(6x - 5y)

Taking (6x - 5y) as common, we get

= (6x - 5y)(9x - 12$x^2$)

Taking 3x as common in second term, we get

= (6x - 5y)(3x)(3 - 4x)

= 3x(6x - 5y)(3 - 4x)

∴ The factorisation of 9x(6x - 5y) - 12$x^2$(6x - 5y) = 3x(6x - 5y)(3 - 4x)

Thus, the factorisation of 9x(6x - 5y) - 12$x^2$(6x - 5y) is equal to 3x(6x - 5y)(3 - 4x).

Answer 2

Answer:

The factorised expression to the given expression is 3x(3-4x)(6x-5y)

Therefore $9x(6x-5y)-12x^2(6x-5y)=3x(3-4x)(6x-5y)$

Step-by-step explanation:

Given that the expression is $9x(6x-5y)-12x^2(6x-5y)$

To factorise the given polynomial :

$9x(6x-5y)-12x^2(6x-5y)$

$=(9x-12x^2)(6x-5y)$

$=3x(3-4x)(6x-5y)$ ( by taking the common term 3x outside of the expression )

Therefore $9x(6x-5y)-12x^2(6x-5y)=3x(3-4x)(6x-5y)$

The factorised expression to the given expression is 3x(3-4x)(6x-5y)