Question

factorise 9x2+4y2+4z2-6xy-4yz-6zx

Answer 1

Answer:

$(3x + 2y + 2z) ^{2}$

Answer 2

a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

9x2+4y2+4z2-6xy-4yz-6zx

(3x)²+(2y)²+(2z)² -(3x× 2y)-(2y× 2z)-(3x× 2z)=

(a²+b²+c²-ab-bc-ca)

(a²+b²+c²-ab-bc-ca) = (a³+b³+c³-3abc)/(a+b+c)

a = 3x

b= 2y

c= 2z

by putting values

= {(3x)³+(2y)³+(2z)³-3(3x×2y×2z)/(3x+2y+2z)

= 27x³+8y³+8z³-36xyz /3x+2y+2z