Question

Factorise 9x²+4y²+z²-12xy+4yz-6zx.hence, find the value when x=1,y=2 and z=-1

Answer 1

these is the answer boy by formula of algebra

Answer 2

The correct answer is 0.

Given: The equation = 9x²+4y²+z²-12xy+4yz-6zx.

The value of x=1, y=2 and z=-1.

To Find: The value of equation at x=1,y=2 and z=-1.

Solution:

Put the value of x, y and z in 9x²+4y²+z²-12xy+4yz-6zx.

$9(1)^{2} +4(2)^{2} +(-1)^{2} -12(1)(2)+4(2)(-1)-6(-1)(1)$

= 9 + 4(4) + 1 - 24 - 8 + 6

= 9+16+1-24-8+6

= 0

Hence, the answer is 0.

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