Question

factorise 9x²-(x²-4)²​

Answer 1

(3x)²-(x²-4)²

[3x-(x²-4)][3x+(x²-4)]

(3x-x²+4)(3x+x²-4)

Answer 2

Step-by-step explanation:

if one has to get the solution for x then the equation will be

[math]9x^2 --(x^2 -4)^2 =0 [/math]

[math](3x) ^2 -(x^2 -4)^2 =0 [/math]

[math](3x+x^2 -4) (3x -x^2+4)=0 [/math]

[math]If x^2 +3x -4 =0 then [/math]

[math](x +4) (x -1) =0 [/math]

Either [math]x=-4 or x =1. and [/math]

if [math](4 +3x -x^2)=0 then [/math]

[math](4-x)(1+x) =0[/math]

either [math]x=4 or x=-1 [/math]. four roots of x are

x =4; x=-1; x=-4; x =1.