Question

factorise 9x⁴+26x²-3​

Answer 1

$\tt \bigstar\: 9x⁴ + 26x² - 3$

$\tt\implies \: 9x⁴ + 27x² - x² - 3$

$\tt\implies \: 9x² ( x² + 3 ) - 1 ( x² + 3 )$

$\tt\implies( 9x² - 1 ) ( x² + 3 ) = 0$

$\tt \: 9x² - 1 = 0 ⠀⠀⠀⠀x² + 3 = 0$

$\tt \: x² = \frac{1}{9} ⠀⠀⠀⠀⠀⠀⠀x² = - 3$

$\tt \: x = \sqrt{ \frac{1}{9}} ⠀⠀⠀⠀⠀⠀x = \sqrt {- 3}$

$\tt \: x = \frac{1}{3} ⠀⠀⠀⠀⠀⠀⠀⠀x = \sqrt{ - 3}$

$\tt\therefore \: The \: value \: of \: x \: will \: be \: \red{\frac{1}{3}}\: and \: \red{\sqrt{- 3}}$

Answer 2

★9x⁴+26x²−3

\tt\implies \: 9x⁴ + 27x² - x² - 3⟹9x⁴+27x²−x²−3

\tt\implies \: 9x² ( x² + 3 ) - 1 ( x² + 3 )⟹9x²(x²+3)−1(x²+3)

\tt\implies( 9x² - 1 ) ( x² + 3 ) = 0⟹(9x²−1)(x²+3)=0

\begin{gathered} \\ \\ \end{gathered}

\tt \: 9x² - 1 = 0 ⠀⠀⠀⠀x² + 3 = 09x²−1=0⠀⠀⠀⠀x²+3=0

\tt \: x² = \frac{1}{9} ⠀⠀⠀⠀⠀⠀⠀x² = - 3x²=

9

1

⠀⠀⠀⠀⠀⠀⠀x²=−3

\tt \: x = \sqrt{ \frac{1}{9}} ⠀⠀⠀⠀⠀⠀x = \sqrt {- 3}x=

9

1

⠀⠀⠀⠀⠀⠀x=

−3

\tt \: x = \frac{1}{3} ⠀⠀⠀⠀⠀⠀⠀⠀x = \sqrt{ - 3}x=

3

1

⠀⠀⠀⠀⠀⠀⠀⠀x=

−3

\begin{gathered} \\ \end{gathered}

\tt\therefore \: The \: value \: of \: x \: will \: be \: \red{\frac{1}{3}}\: and \: \red{\sqrt{- 3}}∴Thevalueofxwillbe

3

1

and

−3