Math, asked by ahana1848, 1 month ago

Factorise 9y2 - 4xy + 4x^2/9​

Answers

Answered by tannu1826
0

(3y−

3

2

x)

2

Step-by-step explanation:

\begin{gathered}=9y^{2}-4xy+\frac{4x^{2}}{9}\\=(3y)^{2}-2\times3y\times\frac{2}{3}x+(\frac{2}{3}x)^{2}\\ Using (a-b)^{2}=a^{2}-2ab+b^{2} :\\=(3y-\frac{2}{3}x)^{2}\\Hence\: \: proved!\end{gathered}

=9y

2

−4xy+

9

4x

2

=(3y)

2

−2×3y×

3

2

x+(

3

2

x)

2

Using(a−b)

2

=a

2

−2ab+b

2

:

=(3y−

3

2

x)

2

Henceprove

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