Factorise 9y2 - 4xy + 4x^2/9
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(3y−
3
2
x)
2
Step-by-step explanation:
\begin{gathered}=9y^{2}-4xy+\frac{4x^{2}}{9}\\=(3y)^{2}-2\times3y\times\frac{2}{3}x+(\frac{2}{3}x)^{2}\\ Using (a-b)^{2}=a^{2}-2ab+b^{2} :\\=(3y-\frac{2}{3}x)^{2}\\Hence\: \: proved!\end{gathered}
=9y
2
−4xy+
9
4x
2
=(3y)
2
−2×3y×
3
2
x+(
3
2
x)
2
Using(a−b)
2
=a
2
−2ab+b
2
:
=(3y−
3
2
x)
2
Henceprove
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