factorise (a-1)x2+a2xy+(a+1)y2
Anonymous:
(a-1)x^2+a^2xy+(a+1)y^2 is this your equation
no
i am sorry i don't the answer
thanks
Answers
Answered by
149
The answer is given below :
Now,
(a - 1)x² + a²xy + (a + 1)y²
= (a - 1)x² + (a² - 1 + 1)xy + (a + 1)y²
= (a - 1)x² + {(a - 1)(a + 1) + 1}xy + (a + 1)y²
= (a - 1)x² + (a - 1)(a + 1)xy + xy + (a + 1)y²
= (a - 1)x{x + (a + 1)y} + y{x + (a + 1)y}
= (x + ay + y)(ax - x + y)
Thank you for your question.
Now,
(a - 1)x² + a²xy + (a + 1)y²
= (a - 1)x² + (a² - 1 + 1)xy + (a + 1)y²
= (a - 1)x² + {(a - 1)(a + 1) + 1}xy + (a + 1)y²
= (a - 1)x² + (a - 1)(a + 1)xy + xy + (a + 1)y²
= (a - 1)x{x + (a + 1)y} + y{x + (a + 1)y}
= (x + ay + y)(ax - x + y)
Thank you for your question.
Answered by
28
hope this helps you..........
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