Question

factorise=a^12x^4-a^4x^12

Answer 1

hey here is your answer

hope you like this answer

a¹².y⁴ - a⁴.y¹²

you can write a¹² = a⁴.a^8
again, y¹² = y⁴.y^8

now use this,

= a⁴.a^8.y⁴ - a⁴.y⁴.y^8
you see that a⁴.y⁴ are common terms in both so,

= a⁴.y⁴( a^8 - y^8)
[ use,formula , x² - y² = (x - y)(x + y) ]

= a⁴.y⁴(a⁴ - y⁴)(a⁴ + y⁴)

=a⁴.y⁴(a² - y²)(a² + y²)(a⁴+y⁴)

=a⁴.y⁴(a - y)(a+ y)(a²+y²)(a⁴ + y⁴)

make sure it brainliest please

Answer 2

Answer:

Step-by-step explanation:

a¹².y⁴ - a⁴.y¹²

you can write a¹² = a⁴.a^8

again, y¹² = y⁴.y^8

now use this,

= a⁴.a^8.y⁴ - a⁴.y⁴.y^8

you see that a⁴.y⁴ are common terms in both so,

= a⁴.y⁴( a^8 - y^8)

[ use,formula , x² - y² = (x - y)(x + y) ]

= a⁴.y⁴(a⁴ - y⁴)(a⁴ + y⁴)

=a⁴.y⁴(a² - y²)(a² + y²)(a⁴+y⁴)

=a⁴.y⁴(a - y)(a+ y)(a²+y²)(a⁴ + y⁴)

make sure it brainliest please

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