Question

factorise :a ) (2 – 2)^3 + (2 – 2)^3 + (2 – 2)^3

Answer 1

Using formula, if a+b+c=0 , then a^3 +b^3 + c^3= 3abc

so here we let

(2-2)=a

(2-2)=b

(2-2)=c

now,

a+b+c= (2-2)+(2-2)+(2-2)

=0+0+0

a+b+c=0

so,

a^3+ b^3 +c^3=(2-2)^3+(2-2)^3+(2-2)^3=3abc

3×0×0×0

=0