what must be added to x⁴-x³+x²-5x to get x⁴-x2+4?
Answers
do it again and yourself
Answer:
Given⤵
➡ x⁴-x³+x²-5x and x⁴-x2+4.
To find ⤵
➡Value which added to x⁴-x³+x²-5x to get x⁴-x2+4.
Solution⤵
⚫Let assume as what added in 5 to get 8 . Then in simple way we subtract 5 from 8. Then it comes 3.If we add 3 in 5 then it come 8.
⚫Similarly, In this question if we x⁴-x³+x²-5x subtract from x⁴-x2+4 then the answer came.
➡x⁴-x²+4-(x⁴-x³+x²-5x)
➡x⁴-x²+4-x⁴+x³-x²+5x
➡x⁴-x⁴+x³-x²-x²+5x+4
➡x³-2x²+5x+4
✅Hence ,x³-2x²+5x+4 is added to x⁴-x³+x²-5x then we get x⁴-x2+4.
Proof ⤵
➡x³-2x²+5x+4+x⁴-x³+x²-5x= x⁴-x²+4
➡x⁴+x³-x³-2x²+x²+5x-5x+4=x⁴-x²+4
➡x⁴-x²+4=x⁴-x²+4
LHS= RHS
Extra points⤵
✡If it is given that what must be added in A to A+B then we Subtract A From A+B, which comes B.
(A+B) -A➡A+B-A➡B
Proof :- A+B= A+B
LHS=RHS
Hope this is helpful to you!