Math, asked by rishavrajput9122, 1 year ago

factorise
a^2+2ab+b^2-9c^2

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Answered by rk086466

hope this is helpful

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rishavrajput9122: thanks

Answered by hukam0685

this can be represented as
$= {(a + b)}^{2} - ( {3c)}^{2} \\ now \: open \: the \: identity \\ ( {x}^{2} - {y}^{2} ) = (x + y)(x - y) \\ = (a + b + 3c)(a + b - 3c)$
is the answer

rishavrajput9122: i have one more question

rishavrajput9122: please answer this

rk086466: send me

rishavrajput9122: 108a^2-3(b-c)^2

hukam0685: =3(36a^2-(b-c)^2)=3((6a)^2-(b-c)^2)=3(6a+b-c)(6a-b+c)

rk086466: Correct answer

rishavrajput9122: yes sir

hukam0685: you had solve another question from me,and mark other answer as brainliest,you cheated

rishavrajput9122: no no

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factorise a^2+2ab+b^2-9c^2

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factorise
a^2+2ab+b^2-9c^2