Question

Factorise a^2+4b^2-4ab-4c^2

Answer 1

(a-2b)^2-(2c)^2
(a-2b+2c)(a-2b-2c)

Answer 2

Hi ,

a² + 4b² - 4ab - 4c²

= a² + ( 2b )² - 2 × a × 2b - 4c²

= ( a - 2b )² - ( 2c )²

= [ ( a - 2b ) + 2c ] [ ( a - 2b ) - 2c ]

= ( a - 2b + 2c )( a - 2b - 2c )

I hope this helps you.

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