Question

factorise a^2 - 6a -a

Answer 1

$\textbf{- Answer -}$

Now,

a^2 - 6a - a

= a^2 - 7a

= a (a - 7),

which is the required factorization.
___________

Now,

a^2 - a - 6

= a^2 - (3 - 2)a - 6

= a^2 - 3a + 2a - 6

= a (a - 3) + 2 (a - 3)

= (a - 3) (a + 2),

which is the required factorization.

#$\textbf{MarkAsBrainliest}$

Answer 2

Hey dear!!


a²-6a-a !!❎❎

a²-a -6✔✔

Here is yr answer.....


Method l :

=> a²-a-6

=> a² +2a -3a -6

=> a(a+2) -3(a+2)

=> (a+2) (a-3)



a = -2

a = 3



Method ll :


=> a²-a-6

It us in the form of

x²+(a+b)x+ab = (x+a)(x+b)

x = a, a = -3 , b = 2


=> a² + (-3+2)x +(-3)×2

=> (x+(-3) ) (x+2)

=> (x-3)(x+2)


x = 3

x = -2




Hope it hlpz....