Question

factorise a^2 +8a + 16 please answer​

Answer 1

a^2+4a+4a+16

a(a+4)+4(a+4)

(a+4) (a+4)

(a+4)^2.................

Answer 2

$\underline \red{solution}: - \\ \\ = > {a}^{2} + 8a + 16 \\ \\ = > {a}^{2} + 4a + 4a + 16 \\ \\ = > a(4 + a) + 4(a + 4) \\i.e. \\ \\ = > a(4 + a) + 4(4 + a) \\ \\ = > (a + 4)(4 + a) \\ i.e. \\ \\ = > (4 + a)(4 + a) \\ \\ = > {(4 + a)}^{2} \\ \\ \fbox{i \: hope \: it \: helps \: you.}$