Question

factorise(a^2+9b^2-6ab)-4c^2

Answer 1

(a² + 9b² - 6ab) - 4c²

[ a² + (3b)²-2(3ab)] - 4c²

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By formula, (a -b)²=a²+b²-2ab
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(a - 3b)² - 4c²

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By formula, a²-b²=(a-b)(a+b)
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(a - 3b - 4c)(a - 3b + 4c)



I hope this will help you

(-:

Answer 2

Heya ✋

Let see your answer !!!!!!

$(a ^{2} + 9b ^{2} - 6ab) - 4c ^{2} \\ = ((a ^{2} + (3b) ^{2} - 6 \times a \times 3b) \\ - 4c ^{2} \\ = (a - 3b) ^{2} - 4c ^{2} \\ = (a - 3b + 4c)(a - 3b - 4c)$


$we \: had \: appplied \: this \: identity \\ (a ^{2} - b ^{2}) = (a + b)(a - b)$



Thanks :)))))