Factorise a^2+b^2+2ab+2bc+2ca
Answers
Answered by
109
a² + b² + 2ab + 2bc + 2ac
We know, x² + y² + 2xy = (x + y)
Applying formula,we get
(a + b)² + 2(bc + ca)
(a + b)² + 2c(b + a)
(a + b) (a + b + 2c)
Can't be factorized any more.
We know, x² + y² + 2xy = (x + y)
Applying formula,we get
(a + b)² + 2(bc + ca)
(a + b)² + 2c(b + a)
(a + b) (a + b + 2c)
Can't be factorized any more.
Answered by
51
a^2 + b^2 + 2ab + 2bc + 2ca
= [ a^2 + b^2 + 2(a)(b)] + 2c( a + b)
= (a+b)^2 + 2c (a+b)
= (a+b) (a+b + 2c)
= [ a^2 + b^2 + 2(a)(b)] + 2c( a + b)
= (a+b)^2 + 2c (a+b)
= (a+b) (a+b + 2c)
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