Question

factorise a^2-b^2-c^2 +2bc +a+b-c

fast!!!

Answer 1

Answer:

(a + b - c)(a - b + c + 1)

Step-by-step explanation:

Given Equation is a² - b² - c² + 2bc + a + b - c.

It can be written as,

= (a² - b² - c² + 2bc + a + b - c) - ab + ab + ac - ac + bc - bc

'On rearranging the terms' , we get

= a² - ab + ac + a + ab - b² + bc + b - ac + bc - c² - c

= a(a - b + c + 1) + b(a - b + c + 1) - c(a - b - c + 1)

= (a + b - c)(a - b + c + 1).

Hope it helps!