Question

Factorise:(a^2-b^2)(c^2-d^2)-4abcd​

Answer 1

Answer:

(a^2-b^2)(c^2-d^2)-4abcd

=a^2(c^2-d^2)-b^2(c^2-d^2)-4abcd

=a^2c^2-a^2d^2-b^2c^2+b^2d^2-4abcd

=a^2c^2+b^2d^2-2abcd-a^2d^2-b^2c^2-2abcd

=(a^2c^2+b^2d^2-2abcd)-(a^2d^2+b^2c^2+2abcd)

=(ac-bd)^2-(ad+bc)^2

=(ac-bd+ad+bc)(ac-bd-ad-bc) Ans.

Step-by-step explanation:

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