Question

Factorise: (a) 27x3–y3 (b) 8p3 – 125q3​

Answer 1

Answer:

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Answer 2

Answer:

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Step by step solution:

$Given \ 27x^3-y^3 \ and \ 8p^3-125q^3\\\\we \ have \ to \ Factorise \ it\\\\using \ identity \ a^3-b^3=(a-b)(a^2+b^2+ab)\\\\(i) \ 27x^3-y^3=(3x)^3-(y)^2\\\\27x^3-y^3=(3x-y)(9x^2+y^2+3xy)\\\\(ii) \ 8p^3-125q^3=(2p)^3-(5q)^3\\\\8p^3-125q^3=(2p-5q)(4p^2+25q^2+10pq)$

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