Question

factorise: (a+2b)^2+101(a+2b)+100

Answer 1

Hey user here is your answer....

Given---- (a+2b)^2+101(a+2b)+100

◆Let a+2b =x
◆(x)^2+101(x)+100
◆x^2+100x+x+100
◆Taking common
◆x(x+100)+1(x+100)
◆(x+100)(x+1)
◆Put value of x here
◆(a+2b+100)(a+2b+1)
Hope it helps you☺️

Answer 2

Answer:

[(a+b) + 100] [(a+2b) + 1]

Step-by-step explanation:

take (a+2b) as n

n^2 + 101n + 100

n^2 + n + 100n + 100

n(n+1) + 100(n+1)

= (n+100)(n+1)

which is also [(a+b) + 100] [(a+2b) + 1]

hope it helps