Question

Factorise
(a+2b)2-a2

Answer 1

$(a+2b)^2-a^2\\=[(a+2b)+a] \times[(a+2b)-a]$

(by the rule x² - y² = (x+y)×(x-y))

$[a+2b+a] \times[a+2b-a]\\=[2a+2b] \times[2b]\\=[2(a+b)] \times[2b]\\=4b(a+b)$

Answer 2

Answer:

this is the answer of this question