Question

Factorise a^3-12a(a-4)-64

Answer 1

we have to factorise a³ - 12a(a - 4) - 64

solution : here expression is, a³ - 12a(a - 4) - 64

let's try to solve it.

a³ - 12a(a - 4) - 64

= a³ - 12a² + 48a - 64

= a³ - 4a² - 8a² + 32a + 16a - 64

= a²(a - 4) - 8a(a - 4) + 16(a - 4)

= (a - 4)(a² - 8a + 16)

= (a - 4){a² - 4a - 4a + 16}

= (a - 4){a(a - 4) - 4(a - 4)}

= (a - 4)(a - 4)(a - 4)

= (a - 4)³

Therefore the factorisation of a³ - 12a(a - 4) - 64 is (a - 4)³.

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Answer 2

Answer:

here is answer please take