factorise (a+3)² -2(a+3)²
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Answered by
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Answer:
ya
Step-by-step explanation:
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\left(a+3\right)^{2}-2(a+3)^{2}
(a+3)2−2(a+3)2
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(a+3)(a+3)-2(a+3)^{2}
(a+3)(a+3)−2(a+3)2
2
Distribute
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2
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{\color{#c92786}{(a+3)(a+3)}}-2(a+3)^{2}
(a+3)(a+3)−2(a+3)2
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3
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3
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2
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{\color{#c92786}{a(a+3)+3(a+3)}}-2(a+3)^{2}
a(a+3)+3(a+3)−2(a+3)2
3
Distribute
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3
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2
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{\color{#c92786}{a(a+3)}}+3(a+3)-2(a+3)^{2}
a(a+3)+3(a+3)−2(a+3)2
2
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3
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3
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2
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2
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