Factorise a^3 - 2√2b
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(a)³ - (2√2b³)
(a)³ - (√2b)³
we know,
a³ - b³ = (a - b)(a² + ab + b²)
so,
a³ -(√2b)³ = ( a-√2b)(a² + √2²b² + √2ab)
=( a -√2b)(a² + 2b² + √2ab)
hence, ( a -√2b) and ( a² +2b² +√2ab) are the factors of a³ -(2√2b³)
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