factorise
a) 3-27(a-b)^2
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Answer:
expand using identity and multiply 27
3-[27a^2+27b^2-54ab]
3[1-(9a^2+9b^2-18ab)]
3{1-(3a-3b)^2]
3[1-3(a-b)^2]
hope it is correct....
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