factorise a^3-8b^3+1+6ab
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We know , x³+y³+z³-3xyz = (x+y+z)(x²+y²+z²-xy-yz-xz)
Note :- (a)³+(-2b)³+(1)³-3(a)(-2b)(1)
x=a,y=-2b,z=1
Factorization : (a-2b+1)(a²+4b²+1+2ab+2b-a)
Note :- (a)³+(-2b)³+(1)³-3(a)(-2b)(1)
x=a,y=-2b,z=1
Factorization : (a-2b+1)(a²+4b²+1+2ab+2b-a)
chk:
Thank you...
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