Question

Factorise a^3-8b^3+1+6ab

Answer 1

here is the answer. check thw following attachment.

Answer 2

by applying the 4th formula of cubic polynomial we get..
$x ^{3 } + y ^{3} + z ^{3} = \\ \: ({x + y + z})(x ^{2} + y ^{2} + z ^{2} - xy - \\ yz - xz) \\ so \: \: we \: get......$
(a^3+-2b^3+1^3 -3×a×-2b×1)
=(a-2b+1)(a^2+4b^2+1+2ab+2b-a)