Factorise:
a^3+8b^3+64c^3-24abc
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here is your answer..........
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Shreya1001:
srry dear
I have some work now
so I can't answer to your question
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Answered by
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a³ + 8b³ + 64c³ - 24abc
By using ID> a³ + b³ + c³ - 3abc = (a+b+c) (a² +b²+c² -ab -bc -ca)
(a)³ + (-2b)³ + (-4c)³ - 3(a)(-2b)(-4c)
(a - 2b - 4c) { (a)² + (-2b)² + (-4c)² -(a)(-2b) -(-2b)(-4c) - (-4c)(a) }
(a - 2b - 4c) ( a² + 4b² + 16c² + 2ab -8bc + 4ac)
By using ID> a³ + b³ + c³ - 3abc = (a+b+c) (a² +b²+c² -ab -bc -ca)
(a)³ + (-2b)³ + (-4c)³ - 3(a)(-2b)(-4c)
(a - 2b - 4c) { (a)² + (-2b)² + (-4c)² -(a)(-2b) -(-2b)(-4c) - (-4c)(a) }
(a - 2b - 4c) ( a² + 4b² + 16c² + 2ab -8bc + 4ac)
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