factorise a^3-a-120.....
vandanakaushik8:
which chapter this belongs
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Answered by
31
a3−a−120a3−a−120
=(a3−125)−(a−5)=(a3−125)−(a−5)
=(a−5)(a2+5a+25)−(a−5)=(a−5)(a2+5a+25)−(a−5)
=(a−5)(a2+5a+24)
factorization
Answered by
18
Here is ur ans:-
a3−a−120a3−a−120
=(a3−125)−(a−5)=(a3−125)−(a−5)
=(a−5)(a2+5a+25)−(a−5)=(a−5)(a2+5a+25)−(a−5)
=(a−5)(a2+5a+24)
Hope it was helpful
a3−a−120a3−a−120
=(a3−125)−(a−5)=(a3−125)−(a−5)
=(a−5)(a2+5a+25)−(a−5)=(a−5)(a2+5a+25)−(a−5)
=(a−5)(a2+5a+24)
Hope it was helpful
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